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Show that $f: E \rightarrow F$ is onto.

Let $E, F$ be sets and let $f: E \rightarrow F$. Suppose that E and F are non-empty. Show that $f$ is onto.

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I’m not sure what should be done here. Can you help?


Consider any $y \in F$ and an arbitrary $x \in E$.

If $x

ot= y$, then take $f(x)

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